5x^2-4x+8/10=0

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Solution for 5x^2-4x+8/10=0 equation:



5x^2-4x+8/10=0
We multiply all the terms by the denominator
5x^2*10-4x*10+8=0
Wy multiply elements
50x^2-40x+8=0
a = 50; b = -40; c = +8;
Δ = b2-4ac
Δ = -402-4·50·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{40}{100}=2/5$

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